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Linear Graphs

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Lektionsnotizen

Coordinates

  • The Cartesian plane has a horizontal x-axis and vertical y-axis meeting at the origin (0,0).
  • Coordinates are written as (x, y) – x units horizontally, y units vertically.
  • Positive x: right of origin; negative x: left. Positive y: above; negative y: below.
  • Example: (2,5) is 2 right, 5 up; (-1,-4) is 1 left, 4 down.
  • Check the scale on axes – 1 square may not equal 1 unit.

Points on the Cartesian plane

Points on the Cartesian planeO−6−4−2246−6−4−2246xyA(-3, 4)B(3, -2)

Gradient of a Line

  • Gradient measures steepness: for 1 unit right, go up (positive) or down (negative) by the gradient.
  • Gradient = change in y / change in x = rise/run.
  • Find gradient by drawing a right-angled triangle between two points on the line.
  • Uphill lines have positive gradient; downhill lines have negative gradient.
  • Formula: gradient m = (y₂ - y₁) / (x₂ - x₁).
  • To draw a gradient of a/b: move b units right, a units up (positive) or down (negative).

Gradient of a line: rise/run construction

Gradient of a line: rise/run construction

Equations of Straight Lines (y = mx + c)

  • General equation: y = mx + c, where m is gradient and c is y-intercept.
  • y-intercept is where the line crosses the y-axis (x=0).
  • To find equation from graph: find gradient m (rise/run), read y-intercept c, substitute into y = mx + c.
  • If y-intercept not visible, substitute a point (x,y) into y = mx + c to solve for c.
  • Horizontal line: y = c (gradient 0). Vertical line: x = k (gradient undefined).

y = mx + c

y = 2x + 1O−4−22468−3−2−1123xyy = 2x + 1(0, 1)

Drawing Straight Line Graphs

  • Use a table of values – choose at least 3 x-values, compute y, plot points, join with a straight line.
  • Alternatively, start at y-intercept c, then move 1 unit right and m units up (or down if negative).
  • For fractional gradient a/b, move b units right and a units up/down.
  • Always plot at least 3 points to check for errors.

Plotting from a table of values

Plotting y = 2x + 1 from a table of valuesO−6−4−22468−3−2−1123xyy = 2x + 1

Parallel Lines

  • Parallel lines have the same gradient but different y-intercepts.
  • They never intersect.
  • To find equation of a line parallel to y = mx + c through (x₁,y₁): use y = mx + d, substitute point to find d.

Parallel lines

Parallel lines: same gradientO−4−22468−4−3−2−11234xyy = x + 4y = x + 1

Folien

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Übungsfragen

Gratis-Vorschau — 8 von 51 Fragen. Registriere dich, um alle zu sehen.
  1. 1.What is the gradient of the line y = 2x - 3?

    Easy
    • A-3
    • B2
    • C3
    • D-2
  2. 2.What is the y-intercept of the line y = 4x - 6?

    Easy
    • A-4
    • B4
    • C6
    • D-6
  3. 3.A line has gradient 3 and passes through (0, 1). What is its equation?

    Easy
    • Ay = x + 3
    • By = 3x + 1
    • Cy = -3x + 1
    • Dy = 3x - 1
  4. 4.What is the gradient of a horizontal line?

    Easy
    • Aundefined
    • B-1
    • C0
    • D1
  5. 5.What are the coordinates of the origin?

    Easy
    • A(1, 1)
    • B(0, 1)
    • C(1, 0)
    • D(0, 0)
  6. 6.Find the gradient of the line passing through (1, 2) and (3, 6).

    Easy
    • A4
    • B1/2
    • C3
    • D2
  7. 7.What is the equation of the line parallel to y = 5x + 6 that passes through (0, -7)?

    Easy
    • Ay = 5x + 6
    • By = -5x - 7
    • Cy = 5x + 7
    • Dy = 5x - 7
  8. 8.A line has gradient -2 and passes through (0, 4). What is its equation?

    Easy
    • Ay = -2x - 4
    • By = -2x + 4
    • Cy = 2x + 4
    • Dy = 2x - 4

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