Simplifying, expanding and factorising
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Apuntes de la lección
Collecting Like Terms
- Like terms have the same variable(s) raised to the same power; only the coefficients differ. For example, 3x and 5x are like terms, but 3x and 3x2 are not.
- To simplify, add or subtract the coefficients of like terms. Keep the variable part unchanged: 4a + 7a = 11a, and 9b - 2b = 7b.
- Watch signs carefully: when subtracting, distribute the minus sign to every term in the bracket. For example, (3x + 2) - (x - 5) = 3x + 2 - x + 5 = 2x + 7.
- Terms with different variables or powers cannot be combined: 2x + 3y stays as 2x + 3y, and x2 + x stays as x2 + x.
- Always simplify fully: 5x + 3 - 2x + 4 = 3x + 7.
Multiplying a Single Term over a Bracket
- Use the distributive law: a(b + c) = ab + ac. Multiply the term outside by each term inside the bracket.
- Example: 3(2x + 5) = 6x + 15.
- Be careful with negatives: -2(3x - 4) = -6x + 8. The negative multiplies every term inside.
- When the outside term is a variable, multiply coefficients and add powers: 2x(3x2 + 4) = 6x3 + 8x.
- Always simplify the result by collecting like terms if possible.
Expanding Products of Binomials
- Use FOIL (First, Outer, Inner, Last) or the distributive law twice to expand (a + b)(c + d) = ac + ad + bc + bd.
- Example: (x + 3)(x + 2) = x2 + 2x + 3x + 6 = x2 + 5x + 6.
- Common error: (a + b)2 is NOT a2 + b2. Instead, (a + b)2 = a2 + 2ab + b2.
- For three binomials, expand two first, then multiply the result by the third: (x + 1)(x + 2)(x + 3) = (x2 + 3x + 2)(x + 3) = x3 + 6x2 + 11x + 6.
- Always simplify by collecting like terms after expanding.
Factorising by Taking Out Common Factors
- Factorising is the reverse of expanding: write an expression as a product of factors.
- Identify the highest common factor (HCF) of all terms. For example, 6x2 + 9x = 3x(2x + 3).
- Take out the HCF completely: 12x3 - 8x2 = 4x2(3x - 2).
- Common error: taking out only part of the common factor. Always take out the full HCF.
- Check your answer by expanding the bracket to see if you get the original expression.
Factorising Quadratics of the Form x^2 + bx + c
- A quadratic x2 + bx + c factorises as (x + p)(x + q) where p + q = b and pq = c.
- Find two numbers that multiply to give c and add to give b. For x2 + 5x + 6, the numbers are 2 and 3, so (x + 2)(x + 3).
- If c is positive, both p and q have the same sign as b. If c is negative, one is positive and one is negative.
- Example: x2 - x - 6 = (x - 3)(x + 2) because -3 + 2 = -1 and -3 × 2 = -6.
- Always check by expanding your factorisation.
Difference of Two Squares
- The difference of two squares is a special pattern: a2 - b2 = (a + b)(a - b).
- Recognise it when you have a squared term minus another squared term. For example, x2 - 9 = (x + 3)(x - 3).
- Also applies to expressions like 4x2 - 25 = (2x + 5)(2x - 5).
- Note: a sum of squares, a2 + b2, does not factorise over real numbers.
- Use this pattern to factorise quickly and to simplify algebraic fractions.
Factorising Quadratics with Coefficient of x^2 Not 1 (Higher)
- For ax2 + bx + c with a > 1, use the ac method or trial and error.
- Multiply a and c to get ac. Find two numbers that multiply to ac and add to b.
- Rewrite the middle term using those two numbers, then factor by grouping. Example: 2x2 + 7x + 3: ac = 6, numbers 6 and 1, so 2x2 + 6x + x + 3 = 2x(x + 3) + 1(x + 3) = (2x + 1)(x + 3).
- Alternatively, use trial and error: (2x + 1)(x + 3) works because 2x × 3 + 1 × x = 7x.
- Always check by expanding.
Simplifying Algebraic Fractions
- To simplify an algebraic fraction, factorise the numerator and denominator completely, then cancel common factors.
- Example: \frac{x2 - 9}{x2 + 5x + 6} = \frac{(x + 3)(x - 3)}{(x + 3)(x + 2)} = \frac{x - 3}{x + 2}.
- Common error: cancelling individual terms instead of factors. You can only cancel factors that are multiplied, not terms that are added or subtracted.
- Retain every original denominator restriction. In (x² − 9)/(x² + 5x + 6), x must differ from both −3 and −2, even after cancelling x + 3.
- Always factorise fully before cancelling.
Common Misconceptions and Errors
- Failing to distribute a negative across every term in a bracket: -2(x - 3) = -2x + 6, not -2x - 3.
- Believing (a + b)2 = a2 + b2: the correct expansion is a2 + 2ab + b2.
- Taking out only part of the common factor: always take the highest common factor.
- Cancelling terms in algebraic fractions: cancel factors, not terms. For example, \frac{x + 2}{x} cannot be simplified to 2.
- Losing solutions by cancelling factors that could be zero: when solving equations, don't cancel a variable factor unless you consider the case where it equals zero.
Typical Question Forms
- Expand and simplify products of brackets, e.g., (x + 4)(x - 1).
- Factorise fully a quadratic expression, e.g., x2 - 7x + 12.
- Simplify an algebraic fraction, e.g., \frac{x2 - 4}{x2 - 4x + 4}.
- Show that two expressions are equivalent by simplifying or expanding both.
- Write and simplify an expression for the area or perimeter of a shape with algebraic side lengths.
Diapositivas
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Preguntas de práctica
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1.Which of the following is the correct definition of 'like terms'?
Easy- ATerms that have the same variable(s) raised to the same power(s)
- BTerms that have the same numerical coefficient
- CTerms that have the same variable(s) regardless of power
- DTerms that are equal in value
2.The expression 4x + 3y - 2x + y simplifies to 2x + 4y.
EasyTrue or false?
3.Simplify: 7a + 3b - 2a + 5b
Easy- A5a + 8b
- B9a + 8b
- C5a - 2b
- D9a - 2b
4.Expand and simplify: (x + 3)(x + 5)
Medium- Ax2 + 8x + 15
- Bx2 + 15x + 8
- Cx2 + 2x + 15
- Dx2 + 8x + 8
5.Factorise completely: 6x2 + 9x
Medium- A3x(2x + 3)
- B3(2x2 + 3x)
- Cx(6x + 9)
- D3x(2x2 + 3)
6.Which of the following are equivalent to x2 - 9? (select all that apply)
Medium- A(x - 3)(x + 3)
- B(x - 3)2
- Cx2 - 6x + 9
- D(x + 3)(x - 3)
- Ex(x - 9)
7.Match each expression with its simplified form.
Medium- 2x + 3x
- 2x × 3x
- 2x2 + 3x2
- 5x
- 6x2
- 5x2
8.Arrange the steps to factorise x2 + 7x + 12 in the correct order.
Medium- Find two numbers that multiply to 12 and add to 7
- Write the factorised form: (x + 3)(x + 4)
- Identify the quadratic is of the form x2 + bx + c
- Check the numbers 3 and 4 satisfy the conditions
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