BETAEsta plataforma está en desarrollo activo; hay errores, funciones faltantes y riesgo de pérdida de datos. ¡Gracias por tu apoyo!

Coordinate Geometry

Apréndelo jugando

Responde estas preguntas para ganar energía, luego pesca y explora. Sin cuenta.

Para profes: diapositivas de la lección, apuntes de repaso listos para usar sobre Coordinate Geometry (Maths [CIE], Extended) — úsalos en tu lección, o presenta el tema como una actividad interactiva de clase que tus estudiantes juegan como un juego en vivo.

Apuntes de la lección

Coordinates

  • The Cartesian plane has a horizontal x-axis and vertical y-axis meeting at the origin (0,0).
  • Coordinates are written as (x, y) – x is horizontal, y is vertical.
  • Positive x: right of origin; negative x: left. Positive y: above; negative y: below.
  • Mnemonic: "Along the corridor, up the stairs" (x then y).
  • Check the scale on axes – 1 square may not equal 1 unit.

Points on the Cartesian plane

Points A and BO−6−4−2246−6−4−2246xyA(-3, 4)B(3, -2)

Midpoint of a Line

  • The midpoint is the average (mean) of the endpoints' coordinates.
  • Formula: midpoint = ( (x₁+x₂)/2 , (y₁+y₂)/2 ).
  • Example: A(-4,3) and B(8,-12) → midpoint = (2, -4.5).

Midpoint of AB

Midpoint of ABO−10−55−6−4−2246810xyA(-4, 3)M(2, -4.5)B(8, -12)

Gradient of a Line

  • Gradient measures steepness: rise/run (change in y over change in x).
  • Positive gradient: line goes uphill (bottom-left to top-right).
  • Negative gradient: line goes downhill (top-left to bottom-right).
  • Formula: gradient m = (y₂ - y₁)/(x₂ - x₁).
  • To draw a gradient, e.g. 2/3: move 3 right, 2 up. For -5: move 1 right, 5 down.
  • A gradient of 3 is steeper than 2; -5 is steeper than -4.

Gradient as rise over run

Gradient as rise over runO12345678−1−0.50.511.52xygradient= 3 / 1 =3

Length of a Line

  • Distance between two points uses Pythagoras' theorem.
  • Formula: d = √[(x₁ - x₂)² + (y₁ - y₂)²].
  • Be careful with negative coordinates – use brackets to avoid errors.
  • Example: A(3,-4) and B(-5,2) → d = √(8² + (-6)²) = √100 = 10 units.

Length of AB

Length of ABO−6−4−224−6−4−224xyB(-5, 2)AB = 10A(3, -4)

Diapositivas

Sign up free to view the lesson slides

Step through every slide for this topic — plus flashcards and revision notes — with a free account.

Preguntas de práctica

Vista previa gratis — 8 de 48 preguntas. Regístrate para verlas todas.
  1. 1.What is the midpoint of the line segment joining A(1, 3) and B(5, 8)?

    Easy
    • A(3, 5.5)
    • B(2, 2.5)
    • C(6, 11)
    • D(4, 5)
  2. 2.The point A has coordinates (5, −4). The point B has coordinates (13, 1). Work out the coordinates of the midpoint of AB.

    Easy
    • A(9, -1.5)
    • B(8, -3)
    • C(18, -3)
    • D(9, 2.5)
  3. 3.Find the gradient of the straight line with equation 5x + 2y = 7.

    Medium
    • A-5/2
    • B5/2
    • C-2/5
    • D2/5
  4. 4.Line L has equation y = 2 − 3x. Write down the gradient of line L.

    Easy
    • A-3
    • B3
    • C2
    • D-2
  5. 5.Find the mid-point of AB where A = (w, r) and B = (3w, t). Give your answer in its simplest form in terms of w, r and t.

    Medium
    • A(2w, (r+t)/2)
    • B(4w, r+t)
    • C(2w, r+t)
    • D(w, (r+t)/2)
  6. 6.A is the point (2, 3) and B is the point (7, −5). Find the coordinates of the midpoint of AB.

    Easy
    • A(4.5, -1)
    • B(9, -2)
    • C(4.5, 1)
    • D(5, -2)
  7. 7.Point A has coordinates (5, 8) and point B has coordinates (9, −4). Work out the gradient of AB.

    Easy
    • A-3
    • B3
    • C-1/3
    • D1/3
  8. 8.A straight line joins the points (3k, 6) and (k, −5). The line has a gradient of 2. Find the value of k.

    Medium
    • A11/2
    • B11/4
    • C11
    • D-11/2

Unlock all 48 questions & more

Crea una cuenta gratis para ver todas las preguntas, las diapositivas, las tarjetas y los apuntes de repaso de este tema.

Exámenes anteriores

La práctica con exámenes anteriores de este tema llegará pronto.
Próximamente