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Trigonometry

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Notes

Trigonometry Basics

  • Trigonometry is the mathematics of angles in triangles, studying relationships between side lengths and angles.
  • The three trigonometric functions are **sine**, **cosine**, and **tangent** (sin, cos, tan).
  • These functions are ratios of side lengths in **right-angled triangles**.
  • SOHCAHTOA is a mnemonic to remember the ratios: **S**in = **O**pposite/**H**ypotenuse, **C**os = **A**djacent/**H**ypotenuse, **T**an = **O**pposite/**A**djacent.
  • Trigonometry (like Pythagoras) can only be used in **right-angled triangles**.
  • Ensure your calculator is set to **degrees** (D or Deg on screen).

Labelling Sides of a Right-Angled Triangle

  • Label the sides relative to a chosen angle θ: **Hypotenuse (H)** – longest side, opposite the right angle.
  • **Opposite (O)** – side directly opposite angle θ.
  • **Adjacent (A)** – side next to angle θ (not the hypotenuse).
  • H is always the same; O and A change depending on which angle is θ.

Finding Missing Lengths Using SOHCAHTOA

  • **Step 1:** Label the sides as H, O, A relative to the given angle.
  • **Step 2:** Identify which ratio to use: given two sides, find the two letters in SOHCAHTOA (e.g., O and A → tan).
  • **Step 3:** Substitute values into the formula: e.g., tan(θ) =OA= \frac{O}{A}.
  • **Step 4:** Rearrange to solve for the unknown side (multiply or divide).
  • **Step 5:** Type into calculator and round to **3 significant figures** unless otherwise stated.
  • Example: If tan(43)=x9\tan (43^{\circ}) = \frac{x}{9}, then x=9×tan(43)=8.39x = 9 \times \tan (43^{\circ}) = 8.39 cm (3 s.f.).

Finding Missing Angles Using SOHCAHTOA

  • **Step 1:** Label sides as H, O, A relative to the unknown angle.
  • **Step 2:** Identify the ratio using the two given side letters (e.g., A and H → cos).
  • **Step 3:** Write the ratio as a fraction: cos(θ) =AH= \frac{A}{H}.
  • **Step 4:** Use the **inverse trigonometric function** (sin⁻¹, cos⁻¹, tan⁻¹) – press SHIFT on calculator.
  • **Step 5:** Calculate and round to **1 decimal place** unless otherwise stated.
  • Example: If cos(y)=823\cos (y) = \frac{8}{23}, then y=y = cos⁻¹(8/23) =69.6(1d.p.)= 69.6^{\circ} (1 d.p.).

Common Exam Tips

  • Always label the triangle first before applying SOHCAHTOA.
  • Write down the ratio you are using to avoid mistakes.
  • For lengths, round to **3 significant figures**; for angles, round to **1 decimal place**.
  • Check your calculator mode: it must be in **degrees**.
  • SOHCAHTOA only works in **right-angled triangles** – do not use it for non-right triangles.

Labelling Sides of a Right-Angled Triangle

Adjacent (A)Opposite (O)Hypotenuse (H)θ

SOHCAHTOA Triangle

AOHθSOH CAH TOAsin = O/H, cos = A/H, tan = O/A

Finding a Length Example

9 cmx cm43°tan(43°) = x/9x = 9 × tan(43°) = 8.39 cm

Finding an Angle Example

8 cm23 cmcos(y) = 8/23y = cos⁻¹(8/23) = 69.6°

Practice questions

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  1. 1.In a right-angled triangle, which side is the hypotenuse?

    Easy
    • AThe side opposite the right angle
    • BThe side opposite the given angle
    • CThe side adjacent to the given angle
    • DThe shortest side
  2. 2.What does SOHCAHTOA stand for?

    Easy
    • ASin=Opposite/Hypotenuse,Cos=Adjacent/Hypotenuse,Tan=Opposite/AdjacentSin = Opposite/Hypotenuse, Cos = Adjacent/Hypotenuse, Tan = Opposite/Adjacent
    • BSin=Adjacent/Hypotenuse,Cos=Opposite/Hypotenuse,Tan=Adjacent/OppositeSin = Adjacent/Hypotenuse, Cos = Opposite/Hypotenuse, Tan = Adjacent/Opposite
    • CSin=Hypotenuse/Opposite,Cos=Hypotenuse/Adjacent,Tan=Adjacent/OppositeSin = Hypotenuse/Opposite, Cos = Hypotenuse/Adjacent, Tan = Adjacent/Opposite
    • DSin=Opposite/Adjacent,Cos=Adjacent/Hypotenuse,Tan=Hypotenuse/OppositeSin = Opposite/Adjacent, Cos = Adjacent/Hypotenuse, Tan = Hypotenuse/Opposite
  3. 3.If tan θ =opposite/adjacent= opposite/adjacent, which sides are used for tan?

    Easy
    • AOpposite and adjacent
    • BOpposite and hypotenuse
    • CAdjacent and hypotenuse
    • DHypotenuse and opposite
  4. 4.In a right-angled triangle, the side opposite the angle θ is 5 cm and the hypotenuse is 13 cm. What is sin θ?

    Easy
    • A513\frac{5}{13}
    • B135\frac{13}{5}
    • C1213\frac{12}{13}
    • D512\frac{5}{12}
  5. 5.In a right-angled triangle, the adjacent side is 8 cm and the hypotenuse is 17 cm. What is cos θ?

    Easy
    • A817\frac{8}{17}
    • B178\frac{17}{8}
    • C1517\frac{15}{17}
    • D815\frac{8}{15}
  6. 6.A right-angled triangle has an angle of 30° and an adjacent side of 10 cm. Find the length of the opposite side.

    Medium
    • A5.77 cm
    • B5.00 cm
    • C8.66 cm
    • D11.55 cm
  7. 7.In a right-angled triangle, the opposite side is 12 cm and the hypotenuse is 13 cm. Find the angle θ.

    Medium
    • A67.4°
    • B22.6°
    • C45.0°
    • D60.0°
  8. 8.A right-angled triangle has an angle of 40° and an opposite side of 7 cm. Find the hypotenuse.

    Medium
    • A10.9 cm
    • B9.1 cm
    • C8.4 cm
    • D11.5 cm

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