Area And Perimeter

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Lesson notes

Perimeter

  • Perimeter is the total distance around the outside of a 2D shape; for a circle it is called circumference.
  • Perimeter is a length measured in one dimension, in units such as mm, cm, m.
  • Add together the lengths of all the sides of the shape.
  • For any regular shape, the perimeter is the number of sides multiplied by the length of one side (e.g., square side x cm has perimeter 4x cm).
  • For compound shapes, split into rectangles, triangles or parts of circles, and use properties of shapes (equal sides, Pythagoras' theorem) to find missing lengths.
  • In an L-shape, the sum of the lengths of two shorter sides equals the length of the longer side opposite.

Perimeter of a Compound Shape

Perimeter of a Compound Shape

Worked Example: Compound Shape Perimeter

  • The shape splits into a triangle and two rectangles; the dashes on the triangle show its two slanted sides are equal, so the missing side is 6 cm.
  • The horizontal lengths of the two rectangles add up to the longest horizontal line: 15 + missing = 18, so the missing horizontal length is 3 cm.
  • Add all the sides: 6 + 6 + 18 + 2 + 3 + 4 + 15 = 54 cm.

Compound Shape Perimeter

Compound Shape Perimeter

Area

  • Area is the amount of space within the perimeter of a 2D shape, measured in square units (mm², cm², m²).
  • Rectangle area = length × width (A = lw).
  • Triangle area = ½ × base × perpendicular height (A = ½bh) — this formula is given in the exam.
  • Trapezium area = ½ × (sum of parallel sides) × perpendicular height (A = ½(a+b)h).
  • Parallelogram area = base × perpendicular height (A = bh).
  • The perpendicular height is the distance between the base and the opposite side, not necessarily a side length.

Area Formulas

Area Formulas

Worked Example: Trapezium Area

  • Parallel sides a = 30 cm, b = 15 cm, perpendicular height h = 20 cm.
  • Area = ½ × (30 + 15) × 20 = 450 cm².

Area of a Trapezium

Trapezium30 cm15 cm20 cm

Worked Example: Parallelogram Area

  • Base = 15 cm, perpendicular height = 12 cm.
  • Area = 15 × 12 = 180 cm².

Area of a Parallelogram

Parallelogram15 cm13.42 cm12 cm

Worked Example: Triangle Area

  • Base = 8 cm, perpendicular height = 7 cm.
  • Area = ½ × 8 × 7 = 28 cm².

Area of a Triangle

Right-angled triangle8 cm7 cm

Adding & Subtracting Areas

  • Compound shapes can be split into standard shapes (rectangles, triangles, etc.) and their areas added together.
  • Alternatively, complete the shape into a larger standard shape, then subtract the area of the extra piece added.
  • For the shape shown, the area is the rectangle's area minus the triangle's area.
  • Always check for missing lengths using the given dimensions and the properties of the shapes involved.

Compound Shape by Subtraction

Compound Shape by Subtraction

Worked Example: Compound Shape Area (Pentagon)

  • Split the pentagon into a rectangle (12 cm by 4 cm) and a triangle (base 7 cm, height 5 cm), using the given lengths to find the triangle's base and height.
  • Rectangle area = 12 × 4 = 48 cm²; triangle area = ½ × 7 × 5 = 17.5 cm².
  • Total area = 48 + 17.5 = 65.5 cm².

Compound Shape Area (Pentagon)

Compound Shape Area (Pentagon)

Problem Solving with Areas

  • Real-life problems often involve area and cost (e.g., carpet, paint, tiles) — read the context carefully for key words like area, cost, minimum, maximum.
  • Compound units (e.g. £/m²) hint at which calculations are needed.
  • Annotate diagrams with known and missing lengths as you work through the problem.
  • Compare different options (e.g., companies) by calculating the total cost for each using the area.
  • Show your working even if you don't reach a final answer — marks are given for correct steps.

Splitting a Compound Shape for a Real Problem

Splitting a Compound Shape for a Real Problem

Slides

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Practice questions

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  1. 1.What is the perimeter of a rectangle with length 8 cm and width 5 cm?

    Easy
    • A26 cm
    • B13 cm
    • C40 cm
    • D18 cm
  2. 2.The area of a triangle with base 10 cm and perpendicular height 6 cm is

    Easy
    • A30 cm²
    • B60 cm²
    • C16 cm²
    • D20 cm²
  3. 3.A square has side length 7 cm. Its perimeter is

    Easy
    • A28 cm
    • B49 cm
    • C14 cm
    • D21 cm
  4. 4.The area of a trapezium with parallel sides 12 cm and 8 cm and perpendicular height 5 cm is

    Medium
    • A50 cm²
    • B100 cm²
    • C40 cm²
    • D60 cm²
  5. 5.A rectangle measures 8.5 cm by 10.7 cm, both correct to 1 decimal place. Calculate the upper bound of the perimeter.

    Medium
    • A38.6 cm
    • B38.4 cm
    • C38.2 cm
    • D38.8 cm
  6. 6.The area of triangle ABC is 27 cm² and AB = 6 cm. Calculate the perpendicular height h from AB to C.

    Medium
    • A9 cm
    • B4.5 cm
    • C18 cm
    • D3 cm
  7. 7.An equilateral triangle has side length 12 cm, correct to the nearest centimetre. Find the lower bound of the perimeter.

    Hard
    • A34.5 cm
    • B35.5 cm
    • C36 cm
    • D35 cm
  8. 8.The area of a square is 42.5 cm², correct to the nearest 0.5 cm². Calculate the lower bound of the length of the side.

    Hard
    • A6.48 cm
    • B6.52 cm
    • C6.50 cm
    • D6.46 cm

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