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Dành cho nhà giáo dục: slide bài học, ghi chú ôn tập sẵn dùng cho Iteration and numerical solutions (Mathematics, Algebra) — dùng trong bài giảng của bạn, hoặc chạy chủ đề như một hoạt động lớp học tương tác để người học chơi như một trò chơi trực tiếp.
Iteration repeatedly applies a formula. A suitable formula and starting value may converge to a root; convergence is not guaranteed.
The notation is xn+1 = f(xn), starting from x0 or x1.
Using iteration
Rearrange an equation into the form x = f(x). For x3 - 3x - 1 = 0: x = \frac{x3 - 1}{3} or x = \√[3]{3x + 1}.
For xₙ₊₁ = ∛(3xₙ + 1), starting x₁ = 2 gives x₂ ≈ 1.912931 and x₃ ≈ 1.888835. Continuing converges to about 1.879385; retain calculator precision between steps.
Use the calculator's ANS key to repeat quickly, and keep full calculator accuracy until you round at the end.
Decimal search and change of sign
If f(a) and f(b) have opposite signs, a root of f(x) = 0 lies between a and b (for a continuous function).
Narrow down by testing the midpoint (the decimal search or interval bisection).
To show a root is 1.88 to 2 d.p., show f(1.875) and f(1.885) have opposite signs.
Stating the answer
Give the number of decimal places asked, but check the rounding by looking at when successive iterations agree.
Agreement between a few rounded iterates supports an estimate but is not a proof of accuracy. For a continuous function, a sign-changing interval within the required rounding limits brackets a root.
Slide
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