Differentiation

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课程笔记

Differentiation Basics

Differentiation changes a curve equation y = \ldots into a gradient function \frac{dy}{dx} = \ldots.
To differentiate y = xⁿ, bring down the power and reduce it by one: \frac{dy}{dx} = n x^n-1.
For y = kxⁿ, multiply by the coefficient: \frac{dy}{dx} = kn x^n-1.
Special cases: y = kx gives \frac{dy}{dx} = k; y = c (constant) gives \frac{dy}{dx} = 0.
Differentiate each term separately when a curve has multiple terms.

Finding the Gradient at a Point

To find the gradient at a point, substitute the x-coordinate into \frac{dy}{dx}.
If given a gradient, set \frac{dy}{dx} equal to that value and solve for x.
The y-coordinate is not needed to find the gradient.

Gradient at a point via the tangent

Stationary Points & Turning Points

A stationary point occurs where the gradient is zero: \frac{dy}{dx} = 0.
Turning points are stationary points where the curve changes direction (maxima or minima).
To find coordinates: (1) differentiate, (2) set \frac{dy}{dx} = 0 and solve for x, (3) substitute x into original equation to get y.

Turning points on a cubic curve

Classifying Stationary Points Using Graphs

A positive quadratic (x² positive) has a minimum; a negative quadratic has a maximum.
A positive cubic has a maximum on the left and a minimum on the right.
A negative cubic has a minimum on the left and a maximum on the right.

Classifying turning points on a cubic

Classifying Using the First Derivative

Examine the sign of \frac{dy}{dx} just before and after the stationary point.
If gradient changes from positive to zero to negative → maximum.
If gradient changes from negative to zero to positive → minimum.

Classifying Using the Second Derivative

The second derivative \frac{d²y}{dx²} is the derivative of \frac{dy}{dx}.
Substitute the x-coordinate of the stationary point into \frac{d²y}{dx²}.
If \frac{d²y}{dx²} < 0 → maximum; if \frac{d²y}{dx²} > 0 → minimum; if zero, test fails.

Problem Solving with Differentiation (Optimisation)

Use differentiation to find maximum or minimum values of quantities (e.g., area, volume).
Form an equation for the quantity in terms of one variable, then differentiate and set \frac{dy}{dx} = 0.
Solve for the variable, then substitute back to find the optimum value.
Check if it is a max or min using second derivative or graph shape.

A cuboid with variable dimensions

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练习题

免费预览——50 题中的 8 题。注册即可查看全部。

1.What is the derivative of y = x⁵?
Easy
- A5x⁴
- B5x⁵
- Cx⁴
- D4x⁵
2.What is the derivative of y = 2x³?
Easy
- A6x²
- B5x²
- C2x²
- D6x³
3.What is the derivative of y = 4?
Easy
- A0
- B4
- C1
- D4x
4.What is the derivative of y = 6 + 4x - x²?
Easy
- A4 - 2x
- B4 + 2x
- C6 + 4x - 2x
- D4x - 2x
5.Find the gradient of y = 24 + 5x - x² at x = -1.5.
Medium
- A8
- B2
- C-8
- D-2
6.Given y = 2x^k + u x⁷ and dy/dx = 18 x^k-1 + 21 x⁶, find k and u.
Medium
- Ak=9, u=3
- Bk=9, u=7
- Ck=18, u=21
- Dk=2, u=3
7.Find the x-coordinate of the turning point of y = 6 + 4x - x².
Medium
- A2
- B-2
- C4
- D6
8.Find the coordinates of the turning point of y = 2x² + 8x - 9.
Medium
- A(-2, -17)
- B(2, 15)
- C(-2, 1)
- D(2, -17)

复习笔记

## Differentiation - Quick Revision ### Key Rules - **Power rule**: If \(y = x^n\), then \(\frac{dy}{dx} = n x^{n-1}\). - **Constant multiple**: If \(y = k x^n\), then \(\frac{dy}{dx} = k n x^{n-1}\). - **Linear term**: If \(y = kx\), then \(\frac{dy}{dx} = k\). - **Constant**: If \(y = c\), then \(\frac{dy}{dx} = 0\). - Differentiate term by term for sums/differences. ### Finding Gradient at a Point 1. Differentiate to get \(\frac{dy}{dx}\). 2. Substitute the \(x\)-coordinate into \(\frac{dy}{dx}\). ### Stationary Points (Turning Points) - Set \(\frac{dy}{dx} = 0\) and solve for \(x\). - Substitute \(x\) into original equation to find \(y\). ### Classifying Stationary Points #### Method 1: Second Derivative - Find \(\frac{d^2y}{dx^2}\) by differentiating \(\frac{dy}{dx}\). - If \(\frac{d^2y}{dx^2} < 0\) at the point → **maximum**. - If \(\frac{d^2y}{dx^2} > 0\) at the point → **minimum**. - If \(\frac{d^2y}{dx^2} = 0\), test fails; use another method. #### Method 2: Gradient Table - Check sign of \(\frac{dy}{dx}\) just before and after the point. - Positive → zero → negative: maximum. - Negative → zero → positive: minimum. #### Method 3: Graph Shape - Positive quadratic: minimum. Negative quadratic: maximum. - Positive cubic: max left, min right. Negative cubic: min left, max right. ### Problem Solving (Optimisation) 1. Express quantity in one variable using given constraints. 2. Differentiate and set derivative = 0. 3. Solve for variable. 4. Substitute back to find max/min value. 5. Justify nature (e.g., negative quadratic → max). ### Common Mistakes - Forgetting to substitute \(x\) back into original equation. - Mixing up curve equation and gradient function. - Using \(y\)-coordinate when only gradient is needed.

Differentiation: Algebraic method to find the gradient function (derivative) of a curve.
Gradient function (derivative): A function, written as dy/dx, that gives the gradient of a curve at any point.
Stationary point: A point on a curve where the gradient is zero (dy/dx = 0).
Turning point: A stationary point where the curve changes direction (maximum or minimum).
Maximum point: A turning point where the curve reaches a peak; second derivative < 0.
Minimum point: A turning point where the curve reaches a trough; second derivative > 0.
Second derivative: The derivative of the derivative, denoted d²y/dx²; used to classify stationary points.
Optimisation: Using differentiation to find maximum or minimum values in real-world problems.

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