Kablow!

Parallel and perpendicular lines

Apprends en jouant

Réponds à ces questions pour gagner de l'énergie, puis pêche et explore. Sans compte.

Pour les enseignants : diapos de leçon, notes de révision prêts à l'emploi pour Parallel and perpendicular lines (Mathematics, Algebra) — utilise-les en cours, ou lance le thème en activité de classe interactive que tes apprenants jouent en direct.

Notes de leçon

Parallel lines

  • Distinct non-vertical lines with equal gradients and different intercepts are parallel. Vertical lines are parallel to one another but have undefined gradient.
  • y = 3x + 1 and y = 3x - 4 are parallel (both gradient 3).
  • To find the line parallel to y = 2x + 5 through (1, 9): use m = 2, then 9 = 2(1) + c gives c = 7, so y = 2x + 7.

Same gradient, different intercepts

Same gradient, different interceptsO−10−8−6−4−22468−2−112xyy = 3x + 1y = 3x − 4

Perpendicular lines

  • For two non-vertical lines meeting at a right angle, m₁m₂ = −1. Horizontal and vertical lines are also perpendicular, but the product rule cannot use an undefined gradient.
  • The perpendicular gradient is the negative reciprocal: flip the fraction and change the sign.
  • A line with gradient 2 has a perpendicular gradient -\frac{1}{2}; gradient -\frac{3}{4} gives \frac{4}{3}.

Negative reciprocal gradients

Negative reciprocal gradientsO−4−3−2−11234−4−3−2−11234xyy = 2xy = −½x

Rearranging first

  • Always rearrange to y = mx + c before reading the gradient.
  • 2y = 6x + 4 becomes y = 3x + 2, so m = 3. x + 2y = 8 becomes y = -\frac{1}{2}x + 4, so m = -\frac{1}{2}.

Finding the equation of a parallel or perpendicular line

  • Step 1: find the required gradient. Step 2: substitute the given point into y = mx + c to find c.
  • The line perpendicular to y = 2x + 1 through (4, 3): m = -\frac{1}{2}; 3 = -\frac{1}{2}(4) + c gives c = 5, so y = -\frac{1}{2}x + 5.

Special cases

  • Horizontal lines (y = k) are perpendicular to vertical lines (x = k); their gradients are 0 and undefined.
  • Do not take the reciprocal of zero: a line perpendicular to a horizontal line is vertical, with equation x = k.

Diapos

Sign up free to view the lesson slides

Step through every slide for this topic — plus flashcards and revision notes — with a free account.

Questions d'entraînement

Aperçu gratuit — 8 sur 32 questions. Inscris-toi pour toutes les voir.
  1. 1.What is true of the gradients of distinct non-vertical parallel lines?

    Easy
    • AThey add to zero
    • BThey are equal
    • CThey multiply to -1
    • DThey differ by 1
  2. 2.Which line is parallel to y = 5x + 3?

    Easy
    • Ay = 3x + 5
    • By = 5x - 7
    • Cy = -5x + 3
    • Dy = \frac{x}{5}
  3. 3.What is the gradient of a line parallel to y = -3x + 1?

    Easy
    • A3
    • B-3
    • C\frac{1}{3}
    • D-\frac{1}{3}
  4. 4.What is the gradient of a line perpendicular to y = 4x?

    Easy
    • A4
    • B-4
    • C\frac{1}{4}
    • D-\frac{1}{4}
  5. 5.What is the gradient of a line perpendicular to y = -\frac{2}{5}x?

    Easy
    • A\frac{2}{5}
    • B-\frac{5}{2}
    • C\frac{5}{2}
    • D-\frac{2}{5}
  6. 6.Which pair of lines is perpendicular?

    Easy
    • Ay = 3x and y = 3x + 1
    • By = 3x and y = -\frac{1}{3}x
    • Cy = 3x and y = -3x
    • Dy = 3x and y = \frac{1}{3}x
  7. 7.What is the gradient of y = 6 - 2x?

    Easy
    • A6
    • B-2
    • C2
    • D-6
  8. 8.What is the gradient of 2y = 8x - 6?

    Medium
    • A8
    • B4
    • C2
    • D-3

Unlock all 32 questions & more

Crée un compte gratuit pour voir toutes les questions, les diapos, les cartes mémo et les notes de révision de ce thème.

Annales

Les annales d'entraînement pour ce thème arrivent bientôt.
Bientôt disponible