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Volume And Surface Area

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Notes de leçon

Volume of Cubes and Cuboids

  • Volume of a cuboid: V = lwh (length × width × height).
  • A cube is a special cuboid with all sides equal: V = s³.
  • Terms like 'depth' or 'breadth' may be used instead of height or width.

Cuboid

Cuboid8 cm3 cm5 cm

Volume of Prisms

  • Volume of a prism: V = A × l where A is the cross-sectional area and l is the length.
  • The cross-section is constant throughout the prism.
  • If the volume and length are known, the cross-sectional area can be found by rearranging: A = V / l.

Prism

Prism10 cmCrosssection

Volume of Cylinders

  • Volume of a cylinder: V = πr²h (given in exam).
  • A cylinder is like a prism with a circular cross-section.

Cylinder

Cylinderrh

Volume of Pyramids and Cones

  • Volume of a pyramid: V = (1/3) × base area × perpendicular height.
  • Volume of a cone: V = (1/3)πr²h (given in exam).
  • The height must be perpendicular to the base.

Pyramid

Pyramidh

Volume of Spheres

  • Volume of a sphere: V = (4/3)πr³ (given in exam).
  • A hemisphere is half a sphere: V = (2/3)πr³.

Sphere

Spherer

Problem Solving with Volumes

  • For compound shapes, find volumes of individual parts and add or subtract.
  • For frustums (truncated cones/pyramids), subtract the smaller volume from the larger.
  • Always check units and convert if necessary (e.g., cm to m, litres).
  • Real-world problems often combine volume with cost or capacity.

Frustum of a cone

Frustum of a cone

Surface Area of Cubes, Cuboids, Prisms, and Pyramids

  • Surface area is the sum of the areas of all faces.
  • For flat-faced solids, calculate each face area separately and add.
  • Drawing a net can help visualise all faces.

Net of a pyramid

Net of a pyramidslant height = √(8² + 3²) = 8.54 cm

Surface Area of Cylinders

  • Curved surface area: A = 2πrh (given in exam).
  • Total surface area: A = 2πrh + 2πr² (not given).
  • The net consists of two circles and a rectangle.

Net of a cylinder

Net of a cylindercurved face = 2πr × h = 50.27 cm × 20 cm

Surface Area of Cones

  • Curved surface area: A = πrl where l is slant height (given in exam).
  • Total surface area: A = πrl + πr² (not given).
  • Slant height l can be found using Pythagoras: l = √(r² + h²).

Net of a cone

Net of a conesector radius l = 9.85 cm, angle = 360° × r/l = 146.2°

Surface Area of Spheres and Hemispheres

  • Surface area of a sphere: A = 4πr² (given in exam).
  • Hemisphere curved surface area: 2πr²; total (including base): 3πr².

Surface area of a hemisphere

Surface area of a hemisphere

Diapos

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Questions d'entraînement

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  1. 1.What is the formula for the volume of a cuboid with length l, width w, and height h?

    Easy
    • AV = lwh
    • BV = l + w + h
    • CV = 2lw + 2wh + 2lh
    • DV = l2 + w2 + h2
  2. 2.The volume of a cube is 1000 cm3. What is the side length of the cube?

    Easy
    • A10 cm
    • B100 cm
    • C33.3 cm
    • D31.6 cm
  3. 3.A solid cylinder has radius 3 cm and height 4.5 cm. Calculate its total surface area in terms of π.

    Medium
    • A45π cm2
    • B27π cm2
    • C54π cm2
    • D36π cm2
  4. 4.The volume of a cuboid is 180 cm3 and its base is a square of side 6 cm. What is its height?

    Easy
    • A5 cm
    • B30 cm
    • C3 cm
    • D6 cm
  5. 5.A hemisphere has radius 6 cm. Calculate its volume. Give your answer in terms of π.

    Medium
    • A144π cm3
    • B288π cm3
    • C72π cm3
    • D216π cm3
  6. 6.A solid metal cone has radius 10 cm and height 36 cm. Calculate its volume. Give your answer in terms of π.

    Medium
    • A1200π cm3
    • B3600π cm3
    • C120π cm3
    • D360π cm3
  7. 7.A solid cylinder and a solid sphere have the same radius r. The cylinder has height 8r. What fraction of the cylinder's volume is the sphere's volume?

    Medium
    • A1/6
    • B1/3
    • C1/2
    • D2/3
  8. 8.The surface area of a sphere is 81π cm2. Find the curved surface area of a cylinder with radius 3r and height 8r, where r is the sphere's radius.

    Hard
    • A972π cm2
    • B216π cm2
    • C108π cm2
    • D324π cm2

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