Simple Harmonic Motion
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Describing Oscillations
- An oscillation is the repetitive variation with time of the displacement of an object about an equilibrium position.
- The equilibrium position (x = 0) is where there is no resultant force acting on the object.
- Displacement (x) is the distance of a point from its equilibrium position; it is a vector measured in metres (m).
- Amplitude (x₀) is the maximum value of displacement on either side of the equilibrium position, measured in metres (m).
- Time period (T) is the time for one complete oscillation, measured in seconds (s).
- Frequency (f) is the number of oscillations per second, measured in hertz (Hz); f = 1/T.
- Angular frequency (ω) is the rate of change of angular displacement with respect to time, measured in rad s⁻¹; ω = 2π/T = 2πf.
Simple Harmonic Motion (SHM)
- Simple harmonic motion is a specific type of oscillation where the acceleration is proportional to the displacement and is always directed towards the equilibrium position.
- The defining equation of SHM is a = −ω²x, where a is acceleration (m s⁻²), ω is angular frequency (rad s⁻¹), and x is displacement (m).
- The minus sign shows that acceleration and displacement are always in opposite directions.
- The time period of SHM is independent of the amplitude for small angles of oscillation.
- Examples of SHM include a pendulum, a mass on a spring, and a marble in a bowl.
- A person jumping on a trampoline is not SHM because the restoring force is not proportional to displacement.
Graphical Representation of SHM
- Displacement, velocity and acceleration against time can be represented by sine or cosine curves.
- If oscillations start from the equilibrium position, displacement is a sine curve, velocity is a cosine curve, and acceleration is a negative sine curve.
- If oscillations start from the amplitude position, displacement is a cosine curve, velocity is a negative sine curve, and acceleration is a negative cosine curve.
- The displacement, velocity and acceleration graphs are all 90° out of phase with each other.
- Velocity is the gradient of the displacement-time graph; acceleration is the gradient of the velocity-time graph.
- The acceleration-time graph is a reflection of the displacement-time graph in the x-axis.
Time Period of a Mass–Spring System
- A mass-spring system consists of a mass attached to a spring; the restoring force is F = −kx.
- The time period is given by T = 2π√(m/k), where m is the mass (kg) and k is the spring constant (N m⁻¹).
- This equation applies to both horizontal and vertical mass-spring systems.
- The time period does not depend on the force of gravity, so it is the same on Earth and the Moon.
- A higher spring constant k means a stiffer spring and a shorter time period.
Time Period of a Simple Pendulum
- A simple pendulum consists of a point mass (bob) attached to a light, inextensible string fixed at a point above.
- For small angles (θ < 10°), the time period is T = 2π√(L/g), where L is the length (m) and g is gravitational field strength (N kg⁻¹).
- The small angle approximation sin θ ≈ θ is used to derive this equation.
- The time period depends on gravitational field strength, so it differs on Earth and the Moon.
- The time period is independent of the mass of the bob and the amplitude (for small angles).
Energy Changes in SHM
- In SHM, energy is continuously transferred between potential and kinetic energy.
- For a horizontal mass-spring system, elastic potential energy is maximum at the amplitude positions and zero at equilibrium.
- For a simple pendulum, gravitational potential energy is maximum at the amplitude positions and zero at equilibrium.
- Kinetic energy is maximum at the equilibrium position and zero at the amplitude positions.
- The total energy of an SHM system remains constant, equal to the sum of kinetic and potential energy.
- The total energy is given by E = ½mω²x₀², where m is mass, ω is angular frequency, and x₀ is amplitude.
- The potential energy at displacement x is Eₚ = ½mω²x².
- The kinetic energy at displacement x is Eₖ = ½mω²(x₀² − x²).
Equations for SHM
- For oscillations starting from equilibrium (x = 0 at t = 0): x = x₀ sin ωt, v = ωx₀ cos ωt, a = −ω²x₀ sin ωt.
- For oscillations starting from amplitude (x = x₀ at t = 0): x = x₀ cos ωt, v = −ωx₀ sin ωt, a = −ω²x₀ cos ωt.
- The velocity-displacement relation is v = ±ω√(x₀² − x²).
- Maximum velocity occurs at equilibrium and is vmax = ωx₀.
- Maximum acceleration occurs at amplitude and is amax = ω²x₀.
- These equations are in the data booklet and must be used with radians mode on calculators.
Phase Angles in SHM
- The phase angle φ is the difference in angular displacement compared to an oscillator with x = 0 at t = 0.
- The phase angle can range from 0 to 2π radians.
- With phase angle, the displacement equation becomes x = x₀ sin(ωt + φ).
- A sine wave leads a cosine wave by π/2 radians, or equivalently, cosine lags sine by π/2.
- For a wave that lags, the phase difference is +π/2; for a wave that leads, it is −π/2.
- Sine and cosine functions are out of phase by π/2 radians.
- Phase shifts: sin(ωt − φ) shifts right, sin(ωt + φ) shifts left, cos(ωt − φ) shifts right, cos(ωt + φ) shifts left.
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1.A pendulum oscillates with a time period of 2.2 s. Calculate the frequency of the oscillation.
Easy- A0.45 Hz
- B2.2 Hz
- C4.4 Hz
- D0.22 Hz
2.A mass-spring system oscillates with simple harmonic motion. The total energy of the system is 60 mJ. What is the maximum kinetic energy of the system?
Medium- A60 mJ
- B30 mJ
- C0 mJ
- D120 mJ
3.A mass-spring system oscillates with simple harmonic motion. The graph of potential energy against displacement shows a maximum potential energy of 40 mJ at an amplitude of 0.02 m. What is the total energy of the system?
Medium- A40 mJ
- B20 mJ
- C80 mJ
- D0 mJ
4.A block of mass 25 g oscillates with simple harmonic motion with a maximum kinetic energy of 40 mJ. Calculate the maximum velocity of the block.
Medium- A1.8 m/s
- B0.9 m/s
- C3.2 m/s
- D0.45 m/s
5.A spring has a spring constant of 2.1 N/m. The mass-spring system oscillates with an amplitude of 0.1 m. Calculate the restoring force at the amplitude position.
Medium- A0.21 N
- B2.1 N
- C0.021 N
- D21 N
6.A pendulum bob oscillates with simple harmonic motion. At which position does the pendulum have maximum kinetic energy?
Medium- AAt the equilibrium position
- BAt maximum displacement
- CAt half the amplitude
- DAt the highest point
7.The time period of a simple pendulum depends on its mass.
EasyTrue or false?
8.In simple harmonic motion, the acceleration is always directed towards the equilibrium position.
EasyTrue or false?
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