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Linear Graphs

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Notes de leçon

Equations of Straight Lines (y = mx + c)

  • The general equation is y = mx + c, where m is the gradient and c is the y-intercept.
  • Gradient = rise/run; positive for uphill, negative for downhill.
  • To find the equation from a graph: find gradient using a triangle, read off y-intercept, substitute into y = mx + c.
  • If y-intercept is not visible, substitute a known point into y = mx + c and solve for c.
  • Horizontal lines: y = c; vertical lines: x = k.
  • Rearrange equations like ax + by = c into y = mx + c to identify gradient and intercept.

y = mx + c

y = 2x + 1O−4−22468−3−2−1123xyy = 2x + 1(0, 1)

Drawing Straight Line Graphs

  • Create a table of values for x and y, plot points, and join with a straight line.
  • Use at least 3 points to ensure accuracy.
  • Alternatively, start at y-intercept (c) and move up m units for every 1 unit right (down if m negative).
  • For equations in form ax + by = c, find x-intercept (set y=0) and y-intercept (set x=0), then plot.
  • If gradient is a fraction a/b, go a units up for every b units right.

Drawing straight line graphs from their equations

Drawing straight line graphs from their equations

Parallel Lines

  • Parallel lines have the same gradient.
  • Equation of a line parallel to y = mx + c is y = mx + d (different y-intercept).
  • To find a parallel line through a given point: use same gradient, substitute point to find d.

Parallel lines

Parallel lines: same gradientO−4−22468−4−3−2−11234xyy = x + 4y = x + 1

Perpendicular Lines

  • Perpendicular lines meet at right angles (90°).
  • Gradients m₁ and m₂ satisfy m₁ × m₂ = -1 (negative reciprocals).
  • To find a perpendicular gradient: m₂ = -1/m₁.
  • To find equation of perpendicular line: find negative reciprocal of given gradient, substitute point to find c.
  • A perpendicular bisector cuts a segment in half at right angles; passes through midpoint.

Perpendicular lines

Perpendicular lines: m₁ × m₂ = -1O−22468−2−1123456xyy = 2x(2, 4)y = -0.5x+ 5

Diapos

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Questions d'entraînement

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  1. 1.A straight line, l, has equation y = 5x + 12. What is the gradient of line l?

    Easy
    • A5
    • B12
    • C-5
    • D-12
  2. 2.The line y = 3x − 2 crosses the y-axis at G. What are the coordinates of G?

    Easy
    • A(0, -2)
    • B(0, 2)
    • C(-2, 0)
    • D(2, 0)
  3. 3.Find the coordinates of the point where the line y = 3x − 8 crosses the y-axis.

    Easy
    • A(0, -8)
    • B(0, 8)
    • C(-8, 0)
    • D(8, 0)
  4. 4.Write down the gradient of the line y = 3x − 8.

    Easy
    • A3
    • B-8
    • C-3
    • D8
  5. 5.Find the gradient of a line that is perpendicular to 8y + 4x = 5.

    Medium
    • A2
    • B-2
    • C1/2
    • D-1/2
  6. 6.The equation of line L is 3x − 8y + 20 = 0. Find the gradient of line L.

    Medium
    • A3/8
    • B-3/8
    • C8/3
    • D-8/3
  7. 7.Line L passes through the points (0, -3) and (6, 9). Find the equation of line L.

    Medium
    • Ay = 2x - 3
    • By = 2x + 3
    • Cy = -2x - 3
    • Dy = -2x + 3
  8. 8.Find the gradient of the line that is perpendicular to the line 2y = 3 + 5x.

    Medium
    • A-2/5
    • B2/5
    • C-5/2
    • D5/2

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