Expanding brackets and factorising

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Notes de leçon

Expanding a Single Bracket

  • To expand a bracket, multiply the term outside by each term inside.
  • Example: 3(x + 4) = 3x + 12.
  • Example: 5(2x − 3) = 10x − 15.
  • Remember to multiply both the number and the variable parts.
  • If the term outside is negative, the signs inside the bracket change: −2(x + 5) = −2x − 10.

Expanding and Simplifying Two Brackets

  • To expand (x + a)(x + b), multiply each term in the first bracket by each term in the second.
  • This gives four products: x·x + x·b + a·x + a·b.
  • Simplify by collecting like terms: x2 + (a + b)x + ab.
  • Example: (x + 2)(x + 3) = x2 + 5x + 6.
  • Example: (x − 4)(x + 1) = x2 − 3x − 4.

Squared Brackets

  • A squared bracket like (x + a)2 means (x + a)(x + a).
  • Expand: (x + a)2 = x2 + 2ax + a2.
  • Example: (x + 5)2 = x2 + 10x + 25.
  • Example: (x − 3)2 = x2 − 6x + 9.
  • Be careful: (x + a)2 is not x2 + a2; the middle term 2ax is essential.

Factorising by Taking Out a Common Factor

  • Factorising is the reverse of expanding: write an expression as a product of factors.
  • Find the highest common factor (HCF) of all terms.
  • Write the HCF outside a bracket and divide each term by it inside.
  • Example: 6x + 9 = 3(2x + 3).
  • Example: 4x2 − 8x = 4x(x − 2).
  • Always check by expanding your answer to see if you get the original expression.

Factorising Quadratic Expressions x^2 + bx + c

  • Look for two numbers that multiply to give c and add to give b.
  • Then write the expression as (x + p)(x + q) where p and q are those numbers.
  • Example: x2 + 7x + 12 = (x + 3)(x + 4) because 3 × 4 = 12 and 3 + 4 = 7.
  • Example: x2 − 5x + 6 = (x − 2)(x − 3) because (−2) × (−3) = 6 and (−2) + (−3) = −5.
  • If c is negative, the two numbers have opposite signs.
  • If c is positive and b is negative, both numbers are negative.

Difference of Two Squares

  • The difference of two squares is an expression of the form a2 − b2.
  • It factorises as (a + b)(a − b).
  • Example: x2 − 9 = (x + 3)(x − 3).
  • Example: 4x2 − 25 = (2x + 5)(2x − 5).
  • This pattern works because (a + b)(a − b) = a2 − b2 when expanded.

Checking Your Work

  • After factorising, expand your answer to check it matches the original expression.
  • After expanding, simplify by collecting like terms.
  • Use substitution: pick a value for x and check both expressions give the same result.
  • Common mistake: forgetting to multiply all terms inside the bracket.
  • Common mistake: incorrect signs when expanding or factorising.

Diapos

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Questions d'entraînement

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  1. 1.Expand 3(x + 4).

    Easy
    • A3x + 12
    • B3x + 4
    • Cx + 12
    • D3x − 12
  2. 2.Expand and simplify (x + 2)(x + 5).

    Medium
    • Ax2 + 7x + 10
    • Bx2 + 10x + 7
    • Cx2 + 7x + 7
    • Dx2 + 10
  3. 3.Factorise fully 6x + 9.

    Medium
    • A3(2x + 3)
    • B3(2x + 9)
    • C6(x + 3)
    • D9(x + 1)
  4. 4.Factorise x2 + 7x + 12.

    Medium
    • A(x + 3)(x + 4)
    • B(x + 2)(x + 6)
    • C(x + 1)(x + 12)
    • D(x − 3)(x − 4)
  5. 5.Factorise x2 − 9.

    Medium
    • A(x − 3)(x + 3)
    • B(x − 9)(x + 1)
    • C(x − 3)2
    • D(x − 3)(x − 3)
  6. 6.Which of the following are correct factorisations? (select all that apply)

    Medium
    • Ax2 − 16 = (x − 4)(x + 4)
    • Bx2 + 6x + 8 = (x + 2)(x + 4)
    • C2x + 6 = 2(x + 6)
    • Dx2 − 5x + 6 = (x − 2)(x − 3)
    • Ex2 + 4 = (x + 2)(x + 2)
  7. 7.The expression x2 − 25 can be factorised as (x − 5)(x + 5).

    Easy

    True or false?

  8. 8.Match each expression with its fully factorised form.

    Medium
    • 4x + 8
    • x2 − 1
    • x2 + 5x + 6
    • (x + 2)(x + 3)
    • 4(x + 2)
    • (x − 1)(x + 1)

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