Simple Harmonic Motion

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शिक्षकों के लिए: Simple Harmonic Motion (Physics, HL) के लिए इस्तेमाल के लिए तैयार लेसन स्लाइड्स, रिवीज़न नोट्स — इन्हें अपने लेसन में इस्तेमाल करें, या टॉपिक को एक इंटरैक्टिव क्लास एक्टिविटी की तरह चलाएं जिसे आपके शिक्षार्थी लाइव गेम की तरह खेलें।

लेसन नोट्स

Describing Oscillations

  • An oscillation is the repetitive variation with time of the displacement of an object about an equilibrium position.
  • The equilibrium position (x = 0) is where there is no resultant force acting on the object.
  • Displacement (x) is the distance of a point from its equilibrium position; it is a vector measured in metres (m).
  • Amplitude (x₀) is the maximum value of displacement on either side of the equilibrium position, measured in metres (m).
  • Time period (T) is the time for one complete oscillation, measured in seconds (s).
  • Frequency (f) is the number of oscillations per second, measured in hertz (Hz); f = 1/T.
  • Angular frequency (ω) is the rate of change of angular displacement with respect to time, measured in rad s⁻¹; ω = 2π/T = 2πf.

Simple Harmonic Motion (SHM)

  • Simple harmonic motion is a specific type of oscillation where the acceleration is proportional to the displacement and is always directed towards the equilibrium position.
  • The defining equation of SHM is a = −ω²x, where a is acceleration (m s⁻²), ω is angular frequency (rad s⁻¹), and x is displacement (m).
  • The minus sign shows that acceleration and displacement are always in opposite directions.
  • The time period of SHM is independent of the amplitude for small angles of oscillation.
  • Examples of SHM include a pendulum, a mass on a spring, and a marble in a bowl.
  • A person jumping on a trampoline is not SHM because the restoring force is not proportional to displacement.

Graphical Representation of SHM

  • Displacement, velocity and acceleration against time can be represented by sine or cosine curves.
  • If oscillations start from the equilibrium position, displacement is a sine curve, velocity is a cosine curve, and acceleration is a negative sine curve.
  • If oscillations start from the amplitude position, displacement is a cosine curve, velocity is a negative sine curve, and acceleration is a negative cosine curve.
  • The displacement, velocity and acceleration graphs are all 90° out of phase with each other.
  • Velocity is the gradient of the displacement-time graph; acceleration is the gradient of the velocity-time graph.
  • The acceleration-time graph is a reflection of the displacement-time graph in the x-axis.

Time Period of a Mass–Spring System

  • A mass-spring system consists of a mass attached to a spring; the restoring force is F = −kx.
  • The time period is given by T = 2π√(m/k), where m is the mass (kg) and k is the spring constant (N m⁻¹).
  • This equation applies to both horizontal and vertical mass-spring systems.
  • The time period does not depend on the force of gravity, so it is the same on Earth and the Moon.
  • A higher spring constant k means a stiffer spring and a shorter time period.

Time Period of a Simple Pendulum

  • A simple pendulum consists of a point mass (bob) attached to a light, inextensible string fixed at a point above.
  • For small angles (θ < 10°), the time period is T = 2π√(L/g), where L is the length (m) and g is gravitational field strength (N kg⁻¹).
  • The small angle approximation sin θ ≈ θ is used to derive this equation.
  • The time period depends on gravitational field strength, so it differs on Earth and the Moon.
  • The time period is independent of the mass of the bob and the amplitude (for small angles).

Energy Changes in SHM

  • In SHM, energy is continuously transferred between potential and kinetic energy.
  • For a horizontal mass-spring system, elastic potential energy is maximum at the amplitude positions and zero at equilibrium.
  • For a simple pendulum, gravitational potential energy is maximum at the amplitude positions and zero at equilibrium.
  • Kinetic energy is maximum at the equilibrium position and zero at the amplitude positions.
  • The total energy of an SHM system remains constant, equal to the sum of kinetic and potential energy.
  • The total energy is given by E = ½mω²x₀², where m is mass, ω is angular frequency, and x₀ is amplitude.
  • The potential energy at displacement x is Eₚ = ½mω²x².
  • The kinetic energy at displacement x is Eₖ = ½mω²(x₀² − x²).

Equations for SHM

  • For oscillations starting from equilibrium (x = 0 at t = 0): x = x₀ sin ωt, v = ωx₀ cos ωt, a = −ω²x₀ sin ωt.
  • For oscillations starting from amplitude (x = x₀ at t = 0): x = x₀ cos ωt, v = −ωx₀ sin ωt, a = −ω²x₀ cos ωt.
  • The velocity-displacement relation is v = ±ω√(x₀² − x²).
  • Maximum velocity occurs at equilibrium and is vmax = ωx₀.
  • Maximum acceleration occurs at amplitude and is amax = ω²x₀.
  • These equations are in the data booklet and must be used with radians mode on calculators.

Phase Angles in SHM

  • The phase angle φ is the difference in angular displacement compared to an oscillator with x = 0 at t = 0.
  • The phase angle can range from 0 to 2π radians.
  • With phase angle, the displacement equation becomes x = x₀ sin(ωt + φ).
  • A sine wave leads a cosine wave by π/2 radians, or equivalently, cosine lags sine by π/2.
  • For a wave that lags, the phase difference is +π/2; for a wave that leads, it is −π/2.
  • Sine and cosine functions are out of phase by π/2 radians.
  • Phase shifts: sin(ωt − φ) shifts right, sin(ωt + φ) shifts left, cos(ωt − φ) shifts right, cos(ωt + φ) shifts left.

स्लाइड्स

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प्रैक्टिस सवाल

फ्री प्रीव्यू — 64 में से 8 सवाल। सभी देखने के लिए साइन अप करें।
  1. 1.A pendulum oscillates with a time period of 2.2 s. Calculate the frequency of the oscillation.

    Easy
    • A0.45 Hz
    • B2.2 Hz
    • C4.4 Hz
    • D0.22 Hz
  2. 2.A mass-spring system oscillates with simple harmonic motion. The total energy of the system is 60 mJ. What is the maximum kinetic energy of the system?

    Medium
    • A60 mJ
    • B30 mJ
    • C0 mJ
    • D120 mJ
  3. 3.A mass-spring system oscillates with simple harmonic motion. The graph of potential energy against displacement shows a maximum potential energy of 40 mJ at an amplitude of 0.02 m. What is the total energy of the system?

    Medium
    • A40 mJ
    • B20 mJ
    • C80 mJ
    • D0 mJ
  4. 4.A block of mass 25 g oscillates with simple harmonic motion with a maximum kinetic energy of 40 mJ. Calculate the maximum velocity of the block.

    Medium
    • A1.8 m/s
    • B0.9 m/s
    • C3.2 m/s
    • D0.45 m/s
  5. 5.A spring has a spring constant of 2.1 N/m. The mass-spring system oscillates with an amplitude of 0.1 m. Calculate the restoring force at the amplitude position.

    Medium
    • A0.21 N
    • B2.1 N
    • C0.021 N
    • D21 N
  6. 6.A pendulum bob oscillates with simple harmonic motion. At which position does the pendulum have maximum kinetic energy?

    Medium
    • AAt the equilibrium position
    • BAt maximum displacement
    • CAt half the amplitude
    • DAt the highest point
  7. 7.The time period of a simple pendulum depends on its mass.

    Easy

    True or false?

  8. 8.In simple harmonic motion, the acceleration is always directed towards the equilibrium position.

    Easy

    True or false?

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