Pressure
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Notes
Pressure & Forces
- **Pressure** is defined as the **force per unit area**.
- Unit: **pascal (Pa)** = 1 N/m².
- Equation: **p = F / A**, where p = pressure (Pa), F = force (N), A = area (m²).
- A given force over a **small area** produces a **large pressure**.
- A given force over a **large area** produces a **small pressure**.
- Example: **Tractors** have large tyres to reduce pressure and avoid sinking into mud.
- Example: **Drawing pins** have a sharp point (small area) to concentrate force and push into walls.
- Example: **High heels** have a small area, exerting high pressure and sinking into soft ground.
Pressure in a Liquid
- Pressure in a liquid **increases with depth** due to the weight of liquid above.
- Pressure also **increases with density** of the liquid.
- At the same depth, pressure acts **equally in all directions**.
- Liquid pressure is given by: **Δp = ρgΔh** (Extended tier only).
- Δp = change in pressure (Pa), ρ = density (kg/m³), g = gravitational field strength (N/kg), Δh = change in depth (m).
- **Total pressure** at a depth includes **atmospheric pressure** (≈ 100 kPa).
- Example: A hole at the bottom of a water column produces a stronger jet than one at the top.
Calculating Pressure in Solids
- Use **p = F / A** for solid objects.
- Weight (force) = mass × gravitational field strength (W = mg).
- Ensure area is in **m²**; convert cm² to m² by dividing by 10 000.
- Worked example: A student of weight 550 N standing on two feet (total area 0.020 m²) exerts pressure = 550 / 0.020 = 27 500 Pa.
Calculating Pressure in Liquids (Extended)
- Use **Δp = ρgΔh** to find pressure difference due to depth.
- Example: At 5.0 m depth in water (ρ = 1000 kg/m³, g = 9.8 N/kg), Δp = 1000 × 9.8 × 5.0 = 49 000 Pa.
- Total pressure = Δp + atmospheric pressure = 49 000 + 100 000 = 149 000 Pa.
- Rearrange: Δh = Δp / (ρg) to find depth from pressure.
Applications of Pressure
- **High pressure** applications: knives, nails, high heels – small area concentrates force.
- **Low pressure** applications: snowshoes, skis, tractor tyres – large area spreads force.
- Adding weight (e.g., roof rack) **increases** pressure on the ground.
- Using narrower skis **increases** pressure on snow.
Gas Pressure (Extended)
- Gas pressure is caused by **molecules colliding** with container walls.
- Increasing temperature **increases** molecular speed and collision frequency, raising pressure.
- Pressure in a gas also varies with depth and density (as a fluid).
Particle arrangement in solids, liquids, and gases – affects pressure transmission.
Practice questions
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1.Pressure is defined as the force per unit _____.
Easy- Aarea
- Bvolume
- Cmass
- Dlength
2.Which of the following is the correct unit for pressure?
Easy- Apascal (Pa)
- Bnewton (N)
- Cmetre squared (m²)
- Dkilogram (kg)
3.A tractor has large tyres to reduce the pressure on the ground. This is because pressure is inversely proportional to:
Easy- Aforce
- Barea
- Cweight
- Dvolume
4.The pressure beneath the surface of a liquid increases with:
Easy- Adepth and density
- Bdepth only
- Cdensity only
- Dsurface area
5.A drawing pin is pushed into a wall with a force of 50 N. The area of the point is 0.02 cm². What is the pressure exerted by the point on the wall?
Medium- A2500 N/cm²
- B250 N/cm²
- C25 N/cm²
- D2.5 N/cm²
6.A student of weight 550 N stands on both feet. The total area of his feet in contact with the ground is 0.020 m². What is the pressure exerted on the ground?
Medium- A27 500 Pa
- B2750 Pa
- C27.5 Pa
- D275 000 Pa
7.A swimmer dives to a depth of 2.0 m in a swimming pool. The density of water is 1000 kg/m³ and gravitational field strength is 10 N/kg. What is the pressure due to the water at that depth?
Medium- A20 000 Pa
- B2000 Pa
- C200 Pa
- D20 Pa
8.A car of weight 20 000 N has four tyres, each with an area of 0.1 m² in contact with the road. What is the total pressure exerted by the car on the road?
Medium- A50 000 Pa
- B200 000 Pa
- C5000 Pa
- D20 000 Pa
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