Gravitational Fields

விளையாடிக் கற்றுக்கொள்ளுங்கள்

ஆற்றல் சம்பாதிக்க இந்த கேள்விகளுக்குப் பதிலளியுங்கள், பின்னர் மீன் பிடித்து ஆராயுங்கள். கணக்கு தேவையில்லை.

கல்வியாளர்களுக்கு: Gravitational Fields (Physics, HL)-க்கான தயாரான பாட ஸ்லைடுகள், திருப்புதல் குறிப்புகள் — உங்கள் பாடத்தில் அவற்றைப் பயன்படுத்தவும், அல்லது கற்பவர்கள் நேரலை விளையாட்டாக விளையாடும் ஊடாடும் வகுப்பு செயல்பாடாக தலைப்பை இயக்கவும்.

பாட குறிப்புகள்

Newton's Law of Gravitation

  • Newton's law of gravitation states that the gravitational force between two point masses is proportional to the product of the masses and inversely proportional to the square of their separation.
  • Equation: F = Gm₁m₂ / r², where F is the gravitational force (N), G is Newton's gravitational constant, m₁ and m₂ are the masses (kg), and r is the distance between their centres (m).
  • The inverse square law means that if the separation is doubled, the force reduces by a factor of (½)² = ¼.
  • The law applies to point masses, but planets and stars can be treated as point masses because their separation is much larger than their radii.
  • The distance r is always measured from the centre of mass of each body, so for an object on or above a planet's surface, r = planet's radius + height above surface.

Gravitational Field Strength

  • A gravitational field is a region of space where a test mass experiences a force due to the gravitational attraction of another mass.
  • Gravitational field strength (g) at a point is defined as the force per unit mass experienced by a test mass at that point: g = F / m.
  • The unit of g is N kg⁻¹.
  • From equating F = mg with Newton's law, g = GM / r², where M is the mass producing the field and r is the distance from its centre.
  • The field strength g depends only on the mass M producing the field, so all objects in that field experience the same g regardless of their own mass.
  • g is inversely proportional to the square of the radial distance: g ∝ 1/r².
  • Factors affecting g at a planet's surface are its radius and its mass (or density).

Gravitational Field Strength

Gravitational Field Strength

Gravitational Field Lines

  • Gravitational field lines show the direction of the gravitational force that would act on a mass placed at that point.
  • Field lines are always directed towards the centre of mass of the body because gravitational forces are always attractive.
  • The gravitational field around a point mass is radial, with field lines pointing radially inwards.
  • A uniform field (e.g. near the Earth's surface) is represented by equally spaced parallel field lines; g is the same throughout.
  • Radial fields are non-uniform: g depends on the distance from the centre of mass.
  • For a uniform sphere, the field outside it is identical to that of a point mass at its centre.

Gravitational Potential

  • Gravitational potential (Vg) at a point is the work done per unit mass in bringing a test mass from infinity to that point.
  • Unit: J kg⁻¹.
  • Equation: Vg = − GM / r, where M is the mass producing the field and r is the distance from its centre.
  • Gravitational potential is always negative because it is defined as zero at infinity, and work must be done to move a mass away from the body towards infinity.
  • As r decreases (closer to the planet), Vg becomes more negative (smaller).
  • As r increases (further away), Vg becomes less negative (larger), approaching zero at infinity.
  • Gravitational potential is a scalar quantity, unlike gravitational field strength which is a vector.

Gravitational Potential Energy

  • Gravitational potential energy (Ep) of two point masses is the work done to assemble the system from infinite separation: Ep = − Gm₁m₂ / r.
  • Near the Earth's surface, where the field is approximately uniform, Ep = mgΔh.
  • The change in GPE when a mass moves between two distances r₁ and r₂ is: ΔEp = Gm₁m₂ (1/r₁ − 1/r₂).
  • The change in gravitational potential between two points is: ΔVg = Gm₁ (1/r₁ − 1/r₂).
  • The work done in moving a mass m through a potential difference ΔVg is: ΔW = mΔVg.
  • The area under a force–distance graph for a gravitational field represents the work done (change in GPE).
  • Work is done when a mass moves against the gravitational field lines (away from the planet).

Gravitational Potential Gradient

  • The gravitational field strength at a point is equal to the negative gradient of a potential–distance graph at that point: g = − ΔVg / Δr.
  • The potential gradient is the rate of change of gravitational potential with respect to displacement in the direction of the field.
  • For a planet, the graph of Vg against r follows a −1/r relation and all values of Vg are negative.
  • The gradient of the Vg–r graph at any point gives the value of g at that point.
  • To find g from the graph, draw a tangent at the point and calculate its gradient.

Gravitational Equipotential Surfaces

  • Equipotential lines (2D) or surfaces (3D) join points that have the same gravitational potential.
  • They are always perpendicular to the gravitational field lines.
  • In a radial field, equipotential lines are concentric circles around the planet and become further apart as distance increases.
  • In a uniform field, equipotential lines are horizontal, parallel, and equally spaced.
  • No work is done when moving along an equipotential surface; work is only done when moving between different equipotential surfaces (ΔV = 0 along an equipotential).

Kepler's Laws of Planetary Motion

  • Kepler's First Law: The orbit of a planet is an ellipse, with the Sun at one of the two foci.
  • Kepler's Second Law: A line segment joining the Sun to a planet sweeps out equal areas in equal time intervals; consequently, planets move faster nearer the Sun and slower further away.
  • Kepler's Third Law: For planets or satellites in circular orbit about the same central body, the square of the time period is proportional to the cube of the orbital radius: T² ∝ r³.
  • The relationship between T and r is: T² = (4π² r³) / (GM), where M is the mass of the central body.
  • A graph of log T against log r gives a straight line, since 2 log T ∝ 3 log r.

Escape Speed

  • Escape speed is the minimum speed that will allow an object to escape a gravitational field with no further energy input.
  • It is the same for all masses in the same gravitational field (e.g. a rocket and a tennis ball on Earth).
  • Escape speed is derived by equating kinetic energy to gravitational potential energy: ½ m vesc² = GMm / r.
  • The mass m cancels, giving: vesc = √(2GM / r).
  • Escape speed depends on the mass and radius of the object creating the field (planet, moon, or black hole).
  • Rockets launched from Earth do not need to reach escape velocity to enter orbit; they are continuously given energy by fuel and thrust.

Orbital Motion, Speed & Energy

  • For a satellite in circular orbit, the gravitational force provides the centripetal force: GMm / r² = mv² / r.
  • The mass of the satellite cancels, giving orbital speed: v = √(GM / r).
  • All satellites, regardless of their mass, travel at the same speed in a particular orbit radius.
  • An orbiting satellite has both kinetic energy (Ek) and gravitational potential energy (Ep); its total energy is constant.
  • For a smaller orbital radius: gravitational force is larger, speed is higher, Ek is greater, Ep is lower, and orbital period T is shorter.
  • For a larger orbital radius: gravitational force is smaller, speed is lower, Ek is lower, Ep is greater, and orbital period T is longer.
  • Total energy = Ek + Ep; as orbital radius decreases, Ek increases and Ep decreases.

Effects of Drag on Orbital Motion

  • Satellites in low orbits (<600 km) may experience viscous drag (air resistance) due to the very low but non-zero density of the upper atmosphere.
  • Drag causes a small dissipation of kinetic energy into thermal energy due to friction between air particles and the satellite's surface.
  • As a satellite loses energy, its orbital radius decreases and it spirals towards the Earth.
  • As the orbit becomes lower, some potential energy is transferred to kinetic energy, so the satellite's speed increases.
  • The increased speed in a lower orbit leads to greater air resistance and greater dissipation of kinetic energy.
  • The satellite's total energy decreases if the overall decrease in potential energy is larger than the overall increase in kinetic energy: ΔEtotal < 0 if ΔEp > ΔEk.

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பயிற்சி கேள்விகள்

இலவச முன்னோட்டம் — 58-இல் 8 கேள்விகள். அனைத்தையும் பார்க்க பதிவு செய்யவும்.
  1. 1.Which of the following best defines a gravitational field?

    Easy
    • AA region of space where a test mass experiences a force due to the gravitational attraction of another mass
    • BA region of space where a test mass experiences a repulsive force
    • CThe force per unit mass experienced by a test mass
    • DThe work done per unit mass in bringing a test mass from infinity
  2. 2.Which equation correctly represents Newton's law of gravitation?

    Easy
    • AF = G m1 m2 / r2
    • BF = G m1 m2 / r
    • CF = G m1 m2 r2
    • DF = m g
  3. 3.Which of the following statements about gravitational field lines are correct? (select all that apply)

    Medium
    • AThey point towards the centre of mass of a body
    • BThey are always directed radially outwards
    • CThey can be used to represent the direction of the gravitational force on a mass placed in the field
    • DThey are equally spaced in a uniform field
    • EThey are always straight lines
  4. 4.Gravitational forces are always attractive.

    Easy

    True or false?

  5. 5.Gravitational potential is a vector quantity.

    Easy

    True or false?

  6. 6.Match each term with its correct definition.

    Medium
    • Gravitational field strength
    • Gravitational potential
    • Escape speed
    • The force per unit mass experienced by a test mass at a point
    • The work done per unit mass in bringing a test mass from infinity to a point
    • The minimum speed that will allow an object to escape a gravitational field with no further energy input
  7. 7.Place the following steps in the correct order to derive the equation for escape speed from a planet of mass M and radius r.

    Medium
    • Set kinetic energy equal to gravitational potential energy: 1/2 m vesc2 = GMm/r
    • Cancel the mass m from both sides
    • Rearrange to make vesc the subject: vesc = √(2GM/r)
  8. 8.Match each gravitational quantity with its correct SI unit.

    Medium
    • Gravitational force
    • Gravitational field strength
    • Gravitational potential
    • Gravitational potential energy
    • N
    • N kg⁻¹
    • J kg⁻¹
    • J

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